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For very high frequency AC supply, a capacitor behaves like a pure conductor. Why ?
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The reactance of a capacitor is XC = \(\frac{1}{2 \pi f C}\), where f is the frequency of the AC supply and C is the capacitance of the capacitor. For very high frequency, f, XC is very small. Hence, for very high frequency AC supply, a capacitor behaves like a pure conductor.
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