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A search coil having 2000 turns with area 1.5 cm2 is placed in a magnetic field of 0.60T. The coil is moved rapidly out of the field in a time of 0.2 second. Calculate the induced emf across the search coil.

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Data: N = 2000, Ai = 1.5 × 10-4 m2, Af = 0,
B = 0.6T, ∆t = 0.2s
Initial flux, NΦf = NBAi = 2000(0.6)(1.5 × 10-4)
= 0.18 Wb
Final flux, NΦf = 0, since the coil is withdrawn out of the field.
Induced emf,e = \(-N \frac{\Delta \Phi_{\mathrm{m}}}{\Delta t}=-N \frac{\Phi_{\mathrm{f}}-\Phi_{1}}{\Delta t}\)
∴ e = \(-\frac{0-0.18}{0.2}\) = 0.9V

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