Dimensions of \({1 \over {{\mu _0}{\varepsilon _0}}}\) where symbols have their usual meaning, are

- [ L
^{-1}T ] - [ L
^{-2}T^{2}] - [ L
^{2}T^{-2}] - [ LT
^{-1}]

Correct option is C ) [ L^{2}T^{-2} ]

**Explaination::**

The velocity of light in vacuum is

c = \({1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}\)

\(\therefore[{1 \over {{\mu _0}{\varepsilon _0}}}]\) = [c^{2}] = [L^{2}T^{-2}]

\(\therefore\) Dimension of \({1 \over {{\mu _0}{\varepsilon _0}}}\)= [L^{2}T^{-2}]