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Dimensions of \({1 \over {{\mu _0}{\varepsilon _0}}}\) where symbols have their usual meaning, are

  1. [ L-1T ]
  2. [ L-2T2 ]
  3. [ L2T-2 ]
  4. [ LT-1 ]
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Correct option is C ) [ L2T-2 ]

Explaination::

The velocity of light in vacuum is

c = \({1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}\)

\(\therefore[{1 \over {{\mu _0}{\varepsilon _0}}}]\) = [c2] = [L2T-2]

\(\therefore\) Dimension of \({1 \over {{\mu _0}{\varepsilon _0}}}\)= [L2T-2]

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