+1 vote
61 views

If α=cos​​​​-1(3/5) , β=tan​​​​-1(1/3), where 0<α,β<π/4 , then α-β is equal to 

A) \(\sin^{-1} {9\over5\sqrt{10}}\) 

B)\(\tan^{-1} ({9\over14})\) 

C)\(\cos^{-1} {9\over5\sqrt{10}}\) 

D)\(\tan^{-1} ({9\over5\sqrt{10}})\)

in Trigonometry by (4.1k points)
reopened by | 61 views

1 Answer

+1 vote
Best answer

Correct answer is A) \(\sin^{-1} {9\over5\sqrt{10}}\) 

Detailed answer 

 

by (4.1k points)
532 questions
525 answers
8 comments
12 users