If α=cos^{-1}(3/5) , β=tan^{-1}(1/3), where 0<α,β<π/4 , then α-β is equal to
A) \(\sin^{-1} {9\over5\sqrt{10}}\)
B)\(\tan^{-1} ({9\over14})\)
C)\(\cos^{-1} {9\over5\sqrt{10}}\)
D)\(\tan^{-1} ({9\over5\sqrt{10}})\)
Correct answer is A) \(\sin^{-1} {9\over5\sqrt{10}}\)
Detailed answer