If α=cos^{-1}(3/5) , β=tan^{-1}(1/3), where 0<α,β<π/4 , then α-β is equal to

A) \(\sin^{-1} {9\over5\sqrt{10}}\)

B)\(\tan^{-1} ({9\over14})\)

C)\(\cos^{-1} {9\over5\sqrt{10}}\)

D)\(\tan^{-1} ({9\over5\sqrt{10}})\)

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Correct answer is A) \(\sin^{-1} {9\over5\sqrt{10}}\)

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