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When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is:

1. 0.67 H
2. 1.67 H
3. 3 H
4. 6 H
in Physics | 2 views

EMF = $$L × \frac{di}{dt}$$
50 = L ×$$\frac{ (5-2)}{0.1}$$ = L × 30
L = $$\frac{5}{3}$$ = 1.67