When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is:
Correct option is 2) 1.67H
Explaination
EMF = \(L × \frac{di}{dt}\)
50 = L ×\(\frac{ (5-2)}{0.1}\) = L × 30
L = \(\frac{5}{3}\) = 1.67