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When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is:

  1. 0.67 H
  2. 1.67 H
  3. 3 H
  4. 6 H
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1 Answer

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Best answer

Correct option is 2) 1.67H 

Explaination

EMF = \(L ×  \frac{di}{dt}\)

50 = L ×\(\frac{ (5-2)}{0.1}\) = L × 30

L = \(\frac{5}{3}\) = 1.67 

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