The correct option is B.
The dimensions of torque and work are equal. Both have dimensions as [ML^{2}T^{-2}]
Explaination:
Work (W) = \(\vec{F}.\vec{s} = Fs cosθ
\)
= [MLT^{-2}][L] = [ML^{2}T^{-2}];
Torque \(=\vec{r}\times\vec{F}=rF\sin\theta\)
= [L] [MLT^{-2}] = [ML^{2}T^{-2}]
So dimension of torque and work are same.
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