The sum of two numbers is 128 and their difference is 16. Find the numbers.

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Let the two numbers be x and y

According to 1^{st} condition ,

x+y=128 ------{1}

According to 2nd condition ,

x-y=16 --------{2}

Adding equation 1 and 2

x+y=128

+ x-y=16

---------------------------

2x=144

x=72

put x=72 in first equation ,

72+y=128

y=128-72=56

y=56

**Hence , the first numbers are 72 and 56**

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