+1 vote
145 views

A metallic ring of mass 1 kg has moment of inertia 1 kg m2 when rotating about one of its diameters. It is molten and remoulded into a thin uniform disc of the same radius. How much will its moment of inertia be, when rotated about its own axis

| 145 views

+1 vote
$$Ir = \frac{1}{2}MR^2 = 1 kg\ m^2$$
$$I_d= \frac{1}{2}MR^2 = I_r$$
$$∴ I_d = 1 kg\ m^2$$