e. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s^{2} , calculate its speed on reaching the ground and the height of the table.

Given: t=2s , g=10 m/s^{2} , u=0 , a=g , s=? , v=?

Solution :

\(s=ut+\tfrac{1}{2} gt^2\)

=\(0\times 1+ \tfrac{1}{2} (10)(1)^2\)

=\( \tfrac{1}{2} (10)\)

s= 5m

v=u+gt

=0+10*1

v=10 m/s

The answer is s= 5m and v=10 m/s

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