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e. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2 , calculate its speed on reaching the ground and the height of the table.

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Given: t=2s , g=10 m/s2 , u=0 , a=g , s=? , v=?

Solution :

\(s=ut+\tfrac{1}{2} gt^2\) 

=\(0\times 1+ \tfrac{1}{2} (10)(1)^2\)

=\( \tfrac{1}{2} (10)\) 

s= 5m 

v=u+gt 

=0+10*1

v=10 m/s

 

The answer is  s= 5m and v=10 m/s

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