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Two particles having mass M1 = 4 gm, M2 = 16 gm. If kinetic energy of both the particle is equal then ratio of their momentum is n : 2 then n is:

(1) 2

(2) 1/2

(3) 4

(4) 1/4

in Physics
reopened | 26 views

$$K_1=K_2$$ --{given}
$$\tfrac{p_1^2}{2m_1}=\tfrac{p_2^2}{2m_2}$$
$$(\tfrac{p_1}{p_2})^2=\tfrac{m_1}{m_2}$$
$$(\tfrac{p_1}{p_2})=\sqrt{\tfrac{m_1}{m_2}}$$
$$\sqrt{m_1}:\sqrt{m_2}$$
given m1=4g m2=16g
$$\sqrt{4}:\sqrt{16}$$
$$\sqrt{1}:\sqrt{4}$$ ⇒1:2n:2 = 1:2
therefore n=1

The answer is option 2) 1/2 , and value of n=1

by Expert (10.7k points)