A system releases 125 kJ of heat while 104 kJ of work is done on the system. Calculate the change in internal energy.
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Given: Q = −125kJ, W= −104kJ
ΔU = Q − W= −125−(−104)
= (−125 + 104) = −21kJ. Negative sign shows that decrease in energy.
This is the change (decrease) in the internal energy.