Given : cost for 250 g glucose = Rs 40 , formula of glucose = C_{6}H_{12}O_{6}
To find : cost of glucose per mole
solution:
molecular formula of glucose = C_{6}H_{12}O_{6}
\(\therefore\) molecular mass of glucose = (6× atomic mass of C)+(12× atomic mass of H) +(6× atomic mass of O)
=(6×12u)+(12×1u)+(6×16u)
=180 u
n(number of moles ) = \(Mass \over molar\space mass \)
=\(250\over180\)
=1.39 mol
price of 1.39 mol is 40 rupees , therefore for 1 mol
price for 1 mol of glucose = \(40\times 1\over 1.39\) = 28.8 Rupees
\(\therefore\) cost per mol of glucose is 28.8 Rs