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I. Calculate the number of moles and molecules of acetic acid present in 22 g of it.
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To find : the number of moles and molecules present in 22 g of acetic acid

Solution :

molecular mass of CH3COOH =(2×atomic mass of C)+(4× atomic mass of H)+(2×atomic mass of  O)

=(2× 12u)+(4×1u)+(2×16u)

=60u

Number of moles =\(mass\over molar \space mass\) 

=\(22\over 60\) 

=0.3667 mol 

Number of molecules = Number of moles × Avogadro's constant 

=0.3667 × 6.022×1023 molecules 

=2.208×1023 molecules

 

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