Pravin has applied a force of 100 N on an object, at an angle of 600 to the horizontal. The object gets displaced in the horizontal direction and 400 J work is done. What is the displacement of the object?
(cos 600 = 1/2)
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Given here is θ=600 and F=100N, while W= 400J , SO s=?
Take the equation W = F s Cos θ
Replace with values 400= 100 × s × ½
Hence, 400 / 100 = ½ × s
4 × 2 = s
Therefore, s=8 m.
The displacement of the object = 8m.