Define the relationship between joule and erg using the equation.

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It is given that 1 newton (1N) = 10^{5} dyne, while 1m = 10^{2} cm. So, if

Work= forces × displacement, then

1 joule = 1 newton × 1 m

1 joule = 10^{5} dyne × 10^{2} cm

= 10^{7} dyne cm.

Hence, 1 joule = 10^{7 }erg.

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