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64 km

solution::

Escape velocity =\(\sqrt{2GM\over R}\)

we know mass remain unchanged

\(V_e' \over V_e\) =\(\sqrt{R_e\over R_e'}\)

\({{10V\over e}\over {V\over e}} ={\sqrt{6400\over R_e'}}\)

\(R_e'=64 km\)

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