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How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?
 

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For x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is given by Ohm's law asVIR
RV/I
Where,
Supply voltage, V= 220 V
Current, I = 5 A
Equivalent resistance of the combination = R,given as

\(\frac{1}{R}=X\times(\frac{1}{176})\)

\(R=\frac{176}{X}\) 

from Ohm's law, 

\(\frac{V}{I}=\frac{176}{X}\) 

\(X=\frac{176\times I}{V}=\frac{176\times 5}{220}=4\)

 

Therefore, four resistors of 176 Ω are required to draw the given amount of current.

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