How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 *V* line?

For *x* number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is given by Ohm's law as*V*= *IR*

*R*= *V*/*I*

Where,

Supply voltage, *V*= 220 *V*

Current, *I* = 5 A

Equivalent resistance of the combination = *R*,given as

\(\frac{1}{R}=X\times(\frac{1}{176})\)

\(R=\frac{176}{X}\)

from Ohm's law,

\(\frac{V}{I}=\frac{176}{X}\)

\(X=\frac{176\times I}{V}=\frac{176\times 5}{220}=4\)

Therefore, four resistors of 176 Ω are required to draw the given amount of current.