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Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

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Given Charge, Q = 96000C
Time, t= 1hr = 60 x 60= 3600s
Potential difference, V= 50volts
Now we know that H= VIt
So we have to calculate I first
As I= Q/t
∴ I = 96000/3600 = 80/3 A

 

\(H=50\times\frac{80}{3}\times60\times60=4.8\times 10^6J\)

 

 

Therefore, the heat generated is 4.8 x 106 J.

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