Given Charge, Q = 96000C

Time, *t*= 1hr = 60 x 60= 3600s

Potential difference, *V*= 50volts

Now we know that *H*= VIt

So we have to calculate *I* first

As *I*= Q/*t*

∴ I = 96000/3600 = 80/3 A

\(H=50\times\frac{80}{3}\times60\times60=4.8\times 10^6J\)

Therefore, the heat generated is 4.8 x 10^{6} J.