Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 *V* each, a 5 Ω resistor, an 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series.

*V* each, a 5 Ω resistor, an 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series.

*V*, each connected in series therefore the potential difference of the battery will be 2 *V* + 2 *V* + 2 *V *= 6*V*. The following circuit diagram shows three resistors of resistances 5 Ω, 8 Ω and 12 Ω respectively connected in series and a battery of potential 6 *V* and a plug key which is closed means the current is flowing in the circuit.