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The oxidation state of Fe in the brown ring complex [Fe(H2O)5NO]SO4 is: 

(a) + 1
(b) + 2
(c) + 3
(d) + 4
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Corret option is a) +1

Explaination ::
[Fe(H2O)5NO]SO\(\rightarrow ([Fe(H_2O)_5NO] )^{+2}+(SO_4)^{-2}\) 

\((fe^+)^{+1} =+2\)

charge on fe= +1

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