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Find out  the number  of  enantiomer, meso isomer  and total number of  optical isomers for  the following  compound 

(a) 3,2,4
(b)  0,2,3
(c) 4,0,4
(d)  0,2,2 
in random by Expert (10.9k points) | 25 views

1 Answer

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Best answer

Correct option is C) 4,0,4

explaination :

Number of enantiomer = 2n (n is the number of chiral carbon )

Number of meso isomer = 0

Total number of optical isomer= 2n + 0 

Solving

Chiral carbon, n= 2

So Number of enantiomer = 2n = 22 = 4

Number of meso isomer = 0

Total number of optical isomer= 2n + 0 = 4+0= 4

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