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Find out  the number  of  enantiomer, meso isomer  and total number of  optical isomers for  the following  compound 

(a) 3,2,4
(b)  0,2,3
(c) 4,0,4
(d)  0,2,2 
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Correct option is C) 4,0,4

explaination :

Number of enantiomer = 2n (n is the number of chiral carbon )

Number of meso isomer = 0

Total number of optical isomer= 2n + 0 

Solving

Chiral carbon, n= 2

So Number of enantiomer = 2n = 22 = 4

Number of meso isomer = 0

Total number of optical isomer= 2n + 0 = 4+0= 4

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