menu search
brightness_auto
more_vert

Find out  the number  of  enantiomer, meso isomer  and total number of  optical isomers for  the following  compound 

(a) 3,2,4
(b)  0,2,3
(c) 4,0,4
(d)  0,2,2 
thumb_up_off_alt 500 like thumb_down_off_alt 0 dislike

1 Answer

more_vert
 
verified
Best answer

Correct option is C) 4,0,4

explaination :

Number of enantiomer = 2n (n is the number of chiral carbon )

Number of meso isomer = 0

Total number of optical isomer= 2n + 0 

Solving

Chiral carbon, n= 2

So Number of enantiomer = 2n = 22 = 4

Number of meso isomer = 0

Total number of optical isomer= 2n + 0 = 4+0= 4

thumb_up_off_alt 500 like thumb_down_off_alt 0 dislike

Related questions

thumb_up_off_alt 500 like thumb_down_off_alt 0 dislike
1 answer
thumb_up_off_alt 500 like thumb_down_off_alt 0 dislike
1 answer
thumb_up_off_alt 500 like thumb_down_off_alt 0 dislike
1 answer
thumb_up_off_alt 501 like thumb_down_off_alt 0 dislike
1 answer
thumb_up_off_alt 500 like thumb_down_off_alt 0 dislike
1 answer

5.2k questions

4.7k answers

75 comments

393 users

...