Find out the number of enantiomer, meso isomer and total number of optical isomers for the following compound

(a) 3,2,4

(b) 0,2,3

(c) 4,0,4

(d) 0,2,2

**Correct option is C) 4,0,4**

**explaination :**

Number of enantiomer = 2n (n is the number of chiral carbon )

Number of meso isomer = 0

Total number of optical isomer= 2^{n} + 0

Solving

Chiral carbon, n= 2

So Number of enantiomer = 2^{n} = 2^{2} = 4

Number of meso isomer = 0

Total number of optical isomer= 2^{n} + 0 = 4+0= 4