Find out the number of enantiomer, meso isomer and total number of optical isomers for the following compound

**Correct option is C) 4,0,4**

**explaination :**

Number of enantiomer = 2n (n is the number of chiral carbon )

Number of meso isomer = 0

Total number of optical isomer= 2^{n} + 0

Solving

Chiral carbon, n= 2

So Number of enantiomer = 2^{n} = 2^{2} = 4

Number of meso isomer = 0

Total number of optical isomer= 2^{n} + 0 = 4+0= 4

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