Area (in sq. units) of the region outside \({|x|\over2}+{|y|\over3}=1\) and inside the ellipse \({x^2\over4}+{y^2\over9}=1\) is

The correct answer is option c) 6(\(\pi-2\))

Explaination::

Area of Ellipse =πab=6π

Area \({|x|\over2}+{|y|\over3}=1\) is

\(={1\over2}(d_1d_2)={1\over2}(4)(6)=12\)

so Area is =6π−12=6(π−2)

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