Area (in sq. units) of the region outside \({|x|\over2}+{|y|\over3}=1\) and inside the ellipse \({x^2\over4}+{y^2\over9}=1\) is
The correct answer is option c) 6(\(\pi-2\))
Explaination::
Area of Ellipse =πab=6π
Area \({|x|\over2}+{|y|\over3}=1\) is
\(={1\over2}(d_1d_2)={1\over2}(4)(6)=12\)
so Area is =6π−12=6(π−2)