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What is the angular momentum of the electron in the third Bohr orbit in the hydrogen atom? (h/2π =1.055 × 10-34 kg m2 / s)

a) 3.165 × 10-34 kg m2 / s

b) 3.165 × 1034 kg m2 / s

c) 3.165 × 10-24 kg m2 / s

d) 3.165 × 102kg m2 / s

 

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1 Answer

 
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Angular momentum of an electron in the nth Bohr orbit of hydrogen atom L=\(nh \over 2\pi\)

For n=3

\(L={3h\over 2\pi}\)

\(L={3\times1.055\times10^{-34}}\)

L=3.165 \(\times 10^{-34} Kg m^2/ s\)

a)option is correct

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