**Two capacitors C _{1} and C_{2} are charged to 120 V and 200 V, respectively. It is found that by connecting them together the potential on each one can be made zero. Then**

(a) 9C

_{1}= 4C_{2}(b) 5C

_{1}= 3C_{2}(c) 3C

_{1}= 5C_{2}(d) 3C

_{1}+ 5C_{2}= 0