# Find the first two terms of the sequence for which Sn is given below Sn=n^2 (n+1)

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Find the first two terms of the sequence for which Sn is given below $$S_n=n^2 (n+1)$$

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Solution ::
To find the first term

substitute n=1 in formula

$$S_1=1^2(1+1)=1(2)=2$$

To find the second term, substitute n = 2 in formula or equation

$$S_2=2^2(2+1)=4(3)=12$$

Now S2 is the sum of the first two terms.

the first term + the second term = 12

2 + the second term = 12

the second term = 12 - 2

the second term = 10

So, the first term = 2 and the second term = 10