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If the current flowing in a coil is reduced to half of its original value, the relation between the new energy (E2) and the original energy (E1) stored in the coil will be

(A) E2 = E1

(B) E2 = 2E1

(C) E2 = \(1\over2\)E1

(D) E2 = \(1\over4 \)E1

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The Correct option is  D)  E2 = \(1\over4\)E 

Explaination  

 Current is become half of the given value. 

\(E={1\over2}Li^2\) 

i.e. 

\({E_2\over E_1}={({i_2\over i_1})^2}=({1\over2})^2\)         __{current halfs i2=1/2 i1}

\(E_2={1\over4}E_1\)

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