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The compound which shows metamerism is :

(1) C5H12

(2) C3H8O

(3) C3H6O

(4) C4H10O

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Correct option is (4) C4H10

This molecular formula is applicable for homologous series ether (–O–) a bivalent functional group and as we know ether with minimum four-C shows metamerism. CH3–CH2–O–CH2–CH3 & CH3–O–CH2–CH2–CH3 are metamers.

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