# An amplitude modulated waves is represented by expression vm = 5(1 + 0.6 cos6280t) sin(211 × 104t) volts

An amplitude modulated waves is represented by expression  $$v_m=5(1+0.6\cos6280t)\sin(211×10^4t) \text{ volts.}$$ The minimum and maximum amplitudes of the amplitude modulated wave are, respectively:

(1) 5V, 8V

(2) 5/2V, 8V

(3) 3V, 5V

(4) 3/2V, 5V

verified

Correct option according to NTA is  $${5\over 2}V , 8V$$

Solution ::

$$V_m=5(5(1+0.6 \cos 6280t)\sin(2π×10^4t)$$

$$V_m=(5+3 \cos 6280t)\sin(2π×10^4t)$$

$$V_{max}= 5+3=8$$

$$V_{min}= 5-3=2$$