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Consider a car moving on a straight road with a speed of 100 m/s. The distance at which a car can be stopped is : (μk = 0.5)

(a) 800 m

(b) 1000 m

(c) 100 m

(d) 400 m

 

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b) is the correct option i.e. 1000 

When the car is stopped by friction then its retarding force is

ma = μR

ma = μmg

a= μg

Consider the equation v2 = u2 -2as (the car is retarding so a is negative)

0 = u2 -2as

2as = u2

s = u2/2a

s = u2/2μg

s = (100)2/2 x 0.5 x 10

s = 1000 m

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