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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10s. Then the coefficient of friction is (consider g =10m/s) 

(a) 0.02

(b) 0.03

(c) 0.06

(d) 0.01

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1 Answer

 
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The correct option is c) 0.06 

Explaination:

u = 6 m/s

v = 0

t =10s

a = -f/m = – μmg/m = – μg = -10μ

Substituting values in v = u+at

0 = 6 – 10μ x 10

Therefore, μ = 0.06

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