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A planet is revolving around sun in elliptical orbit. Maximum & minimum distance of planet from sun are respectively 1.6 × 1012 m and 6 × 1010 m. Find minimum speed if maximum speed of planet is 8 × 104 m/s?

(1) 3 × 104 m/s (2) 3 × 103 m/s (3) 8 × 103 m/s (4) 4 × 104 m/s

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Correct answer is 3) 8\(\times 10^3 m/s\) 

L = mvmaxrmin = m vmin × rmax 

 8 × 104 × 6 × 1010 = vmin × 1.6 × 1012 

vmin = 3 × 103 m/s

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