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A particle of mass m1 = m moving with velocity 10\(\sqrt3\)m/s ˆ i collides with a particle of mass m2 = 2m at rest. After collision m1 comes to rest and m2 breaks into two equal parts such that one part has velocity 10 m/s ˆ j then find the angle the velocity vector of other part makes with x-axis in degrees.

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Correct answer is 30 

\(\vec p_f=\vec p_i\) 

M × 10 \(\hat j\) + m\(\vec v\)= m × 10 \(\sqrt 3\hat i\) 

\(\vec v=10\sqrt3 \hat i+10\hat j\)

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