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A particle of mass rotates in a circle which has a vertical boundary of radius 0.2 meter, rotating in horizontal plane. Mass of the block is 200 gram. It takes 40 second in one complete revolution. Find the normal force on block.

(1) 9.8 × 10–4 N (2) 9.8 × 10–2 N (3) 9.8 N (4) 9.8 × 102 N

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The correct option is option 1) 9.8 × 10–4 N 

\(N=m\omega^2R\) 

\(=(0.2)[{ 4\pi^2\over T^2}](R)\) 

\(=0.2{4(9.8)\over 1600}(0.2)\) 

\(=9.8\times10^{-4} N\)

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