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Relation between voltage, current and resistance is given by $$R={ V\over I}$$ Measured value of voltage (50 $$\pm$$ 2) volt, measured value of current is (20 $$\pm$$2)A. Percentage error in resistance measurement is.:

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Correct Answer for this question is 5

$$R={V\over I}$$

lnR = lnv – lnI

$${{\triangle R\over R}|_{max}}={{\triangle v\over v}+{ \triangle I\over I}}$$

%$$Error = ({2 \over 50}+{.2\over 20} )\times100$$

= (.04+.01) × 100

= .05 × 100 = 5%

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