Relation between voltage, current and resistance is given by \(R={ V\over I}\) Measured value of voltage (50 \(\pm\) 2) volt, measured value of current is (20 \(\pm\)2)A. Percentage error in resistance measurement is.:
Correct Answer for this question is 5
\(R={V\over I}\)
lnR = lnv – lnI
\({{\triangle R\over R}|_{max}}={{\triangle v\over v}+{ \triangle I\over I}}\)
%\(Error = ({2 \over 50}+{.2\over 20} )\times100\)
= (.04+.01) × 100
= .05 × 100 = 5%