the correct answer is 25 N
Given:: \(\mu_s\) = 0.2
Solution::
m=0.5 kg
g=10 m/s^{2}
We know that \(f_s= \mu N\)
To keep the block adhere to the wall
here N = F ...(2)
f_{s} = mg ....(3)
from equation (1), (2), and (3), we get
\(= mg=\mu F\)
\(\therefore F={mg\over\mu}\)
\(F={0.5×10\over0.2}\)
F=25N