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The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be ______ N. [g = 10 ms-2]

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the correct answer is 25 N 

 

Given::  \(\mu_s\) = 0.2 

Solution:: 

m=0.5 kg 

g=10 m/s2 

We know that \(f_s= \mu N\) 

To keep the block adhere to the wall

here N = F ...(2)

fs = mg ....(3)

from equation (1), (2), and (3), we get 

\(= mg=\mu F\) 

\(\therefore F={mg\over\mu}\) 

\(F={0.5×10\over0.2}\)

F=25N

 

 

 

 

 

 

 

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