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An audio signal υm = 20sin2π(1500t) amplitude modulates a carrier υc =80 sin 2π (100,000t). The value of percent modulation is ________.

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Correct answer is 25  

\(v_m = 20 sin [100\pi t+{\pi\over4}] \)

\(:v_c = 80 sin [10^4\pi t+{\pi\over6}] \)

we know that, modulation index =\(A_m\over A_c\) 

from given equations, Am = 20 and Ac = 80 

percentage modulation index =\({A_m\over A_c}\times 100\) 

\(20\over80\) × 100 = 25% 

The value of percentage modulation index is =25

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