Correct Answer is B) 11250 C
Explaination ::
we have ,
i = α_{0}t + βt^{2} , α = 20 A/s and β = 8As^{-2} ,t = 15 sec
We know that ,
\(i={ {dq\over dt}⇒ { \int_0^t idt}=\int_0^Q dq }\)
\(⇒ { \int_0^{15} (α_0t + βt^2)dt}={\int_0^Q dq }\)
\(Q=[ { {α_0t ^2\over2}+{ βt^3\over 3}}]_0^{15}\)
\(Q = 20×15×{15 \over 2 }+ 8×15×15×{15 \over3} – 0\)
Q = 11250 C