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Consider two satellites S1 and S2 with periods of revolution 1 hr and 8 hr respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite S1 to the angular velocity of satellite S2 is

 a. 8: 1

b. 1: 8

c. 2: 1

d. 1: 4

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The correct answer is A) 8:1 

we have formula , \( ω ={ 2\over T}\) 

given the, ratio of time period 

\({T_1\over T_2}={1\over8}\) 

from formula, 

\( ω ∝ { 1\over T}\) 

\({ω_1 \over ω_2} = {T_2 \over T_1}\)   

\({ω_1 \over ω_2} = {8\over 1}\) 

 

\(ω_1: ω_2 = 8 : 1\)

 

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