# Consider two satellites S1 and S2 with periods of revolution 1 hr and 8 hr respectively revolving around a planet in circular orbits.

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Consider two satellites S1 and S2 with periods of revolution 1 hr and 8 hr respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite S1 to the angular velocity of satellite S2 is

a. 8: 1

b. 1: 8

c. 2: 1

d. 1: 4

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The correct answer is A) 8:1

we have formula , $$ω ={ 2\over T}$$

given the, ratio of time period

$${T_1\over T_2}={1\over8}$$

from formula,

$$ω ∝ { 1\over T}$$

$${ω_1 \over ω_2} = {T_2 \over T_1}$$

$${ω_1 \over ω_2} = {8\over 1}$$

$$ω_1: ω_2 = 8 : 1$$