+1 vote
27 views
At what temperature will the rms speed of air molecules be double that NTP?
in physics by Helping Hand (3.2k points)
reopened by | 27 views

1 Answer

+1 vote
Best answer

The correct answer is 1092K or 819°C 

Explanation :: 

We have \(V_{rms}={\sqrt{3RT\over M}}\)  --at T=\(T_0 (NTP)\) 

\(V_{rms}={\sqrt{3RT_0\over M}}\) 

But at temperature T 

\(V_{rms}={2\sqrt{3RT\over M}}\) 

 

\(\therefore \sqrt{3RT\over M}=2{\sqrt{3RT_0\over M}}\) 

\(\sqrt T = \sqrt{4T_0}\) 

T= 4× 273 k 

T=1092 K  

Or 

T=819°C

 

by Helping Hand (3.2k points)

Thanks the answer is correct varified by team Brainiak

744 questions
723 answers
11 comments
24 users