+2 votes

A pulley of radius 2 m is rotated about its axis by a force F =20t-5tnewton (where t is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is 10 kgm2 , the number of rotations made by the pulley before its direction of motion it reversed,


(a) more than 6 but less than 9

(b) more than 9

(c) less than 3

(d) more than 3 but less than 6

in Physics by Expert (10.9k points)
reopened by | 48 views

1 Answer

+2 votes
Best answer

Torque is given by τ = FR

Or α = FR/I


F =20t – 5t2 R = 2m,

I = 10 kgm2

α = \((20t-5t^2)\times2\over 10\)

α = 4t – t 2


\(\omega=\int_t^2\alpha dt=2t^2-t^3/3\)

at \(\omega =0 =2t^2-t^3/3 \)



\(\theta=\int_0^6 \omega dt=\int_0^6(2t^2-t^3/3)dt\)

\(\theta={ 36\over2\pi} <6\)

Hence, your answer should be (d) more than 3 but less than 6

by Expert (10.9k points)
744 questions
723 answers
24 users