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Which of the following is a tautology ? (1) (∼p)∧(p∨q)→q (2) (q→p) ∨∼(p→q) (3) (∼q)∨(p∧q)→q (4) (p→q)∧(q→p)
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option 1) is correct ∼p∧(p∨q)→q
(∼p∧p)∨(∼p∧q)→q
C∨(∼p∧q)→q
(∼p∧q)→q
∼(∼p∧q)∨q
=(p∨∼q)∨q=p∨t=t
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