The line x + y = 2 is tangent to the curve x2 = 3 - 2y at its point
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Avoid writing here -
x2 = 3 – 2y
2x = 0 – 2 (dy / dx)
⇒ dy / dx = – x
The slope of the tangent of the curve is -x.
From the given information of the line,
the slope is -1. So, x = 1 and y = 1.
The required point is (1, 1)