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1 gram of a carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2, The molar mass of M2CO3 in g mol-1 is

(1) 118.6

(2) 11.86

(3) 1186

(4) 84.3

 

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Ans:- 84.3 g/mole 4) is correct option

The equation for the above reaction is as follows:-

M2CO3 + 2HCl-> 2MCl+CO2+2H2O

This shows that ,
1 mole of CO2 is produced from -> 1 mole of M2CO3

Given that,
0.01186 mole of CO2 needs -> 1g of M2CO3

1 mole of CO2 needs -> (1g/0.01186mole)*1 mole = 84.31g

Hence, 84.31g being the mass of 1 mole of the carbonate is its molar mass.
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