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Let a complex number be w = 1 – √3i . Let another complex number z be such that |zw| = 1 and arg(z) – arg(w) = \(\frac{\pi}2\) . Then the area of the triangle with vertices origin, z and w is equal to :

(1) 4

(2) \(\frac 12\)

(3) \(\frac 14\)

(4) 2

in COMPLEX NUMBERS AND QUADRATIC EQUATIONS by Expert (11.5k points) | 25 views

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Correct Answer is (2) 1/2 

Explaination::


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