# How much work is required to form a bubble of 2 cm radius from the soap solution having surface tension 0.07 N/m.

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How much work is required to form a bubble of 2 cm radius from the soap solution having surface tension 0.07 N/m.

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Answer= $$0.703\times 10{-3} J \ \ \ or \ \ \ 7.038\times 10^{-4} J$$

Explaination::

Given::    Radius of the bubble = 2 cm or 0.02 m

Surface tension = 0.07 N/m

Solution::

Initial surface area = 0

Final surface area = $$2\times4 \pi r^2$$

increase in surface area = $$2\times 4\pi r^2$$

Work done = Surface tension x increase in surface area

= 0.07 x $$2\times 4\pi r^2$$

=$$0.07\times 8 \times 3.142 \times (0.02)^2$$

=$$7.038\times 10^{-4}$$ J

or

=$$0.703 \times 10^{-3} J$$