**How much work is required to form a bubble of 2 cm radius from the soap solution having surface tension 0.07 N/m.**

**Answer= \(0.703\times 10{-3} J \ \ \ or \ \ \ 7.038\times 10^{-4} J\)**

**Explaination::**

**Given:: ** Radius of the bubble = 2 cm or 0.02 m

Surface tension = 0.07 N/m

**Solution::**

Initial surface area = 0

Final surface area = \(2\times4 \pi r^2\)

increase in surface area = \(2\times 4\pi r^2\)

Work done = Surface tension** x **increase in surface area

= 0.07 **x** \(2\times 4\pi r^2\)

=\(0.07\times 8 \times 3.142 \times (0.02)^2\)

=\(7.038\times 10^{-4}\) J

or

=\(0.703 \times 10^{-3} J\)